Solvers
Received 2 right answers: Gerard Bouma, Amsterdam, Holland; Kees Kuijk, Twello, Holland; ... CONGRATULATIONS !!
Problem 39
May 2004


problem 39
Solution
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1. Re7+ ; Kh8
1. ... ; Rg7 2. Rg7x+
2. Kh6 ; Re8
2. ... ; Rg6 3. Kg6x ; Rd1x 4. Re8 mate
3. Rd7! ; Kg8
4. Rg7+ ; Kh8
5. Rh7+ ; Kg8
6. Rdg7+ ; Kf8
7. Rh8 mate

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